-10x^2+10=-150

Solution for -10x^2+10=-150 equation:

-10x^2+10=-150

We move all terms to the left:

-10x^2+10-(-150)=0

We add all the numbers together, and all the variables

-10x^2+160=0

a = -10; b = 0; c = +160;
Δ = b2-4ac
Δ = 02-4·(-10)·160
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80}{2*-10}=\frac{-80}{-20}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80}{2*-10}=\frac{80}{-20}
=-4
$